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## Problem #959

### Cm=quy nap \(1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n-1}<n\)

Status: Closed Start Date: 30-12-2011
Priority: Normal Due date:
Assigned to: tanphu % Done:

0%

Category: Quy nạp
Target version: -

Description

Cm=quy nap: \(1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n-1}<n\)
mọi người giúp em... mai em thi rồi!

### History

#### #1, #3314 Updated by tanphuabout 1 year ago

• Subject changed from Cm=quy nap: 1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n-1}<n to Cm=quy nap \(1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n-1}<n\)
• Category set to Quy nạp
• Status changed from New to Assigned
• Assigned to set to tanphu

#### #2, #3315 Updated by tanphuabout 1 year ago

Em xem lại đề có trục trặc không? Thầy chưa thấy quy luật trong tổng ở vế trái.

#### #3, #3316 Updated by icyabout 1 year ago

1/1, 1/2, ..., 1/k, 1/(k+1),... , 1/(2^n-1)

#### #4, #3321 Updated by tanphuabout 1 year ago

• Status changed from Assigned to Closed